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7r^2-13r-2=0
a = 7; b = -13; c = -2;
Δ = b2-4ac
Δ = -132-4·7·(-2)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-15}{2*7}=\frac{-2}{14} =-1/7 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+15}{2*7}=\frac{28}{14} =2 $
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